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The ratio of number of collisions per se...

The ratio of number of collisions per second at the walls of containers by He and `O_(2)` gas molecules kept at same volume and temperature is (assume normal incidence on walls)

A

`2:1`

B

`1:2`

C

`2 sqrt2 :1`

D

`1:2 sqrt2`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of finding the ratio of the number of collisions per second at the walls of containers by helium (He) and oxygen (O₂) gas molecules kept at the same volume and temperature, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding Collision Frequency**: The collision frequency (z) is given by the formula: \[ z = 2 \sigma^2 n v \] where: - \( \sigma \) is the diameter of the gas molecules, - \( n \) is the number density of the gas (number of molecules per unit volume), - \( v \) is the average speed of the gas molecules. 2. **Average Speed of Gas Molecules**: The average speed \( v \) of gas molecules can be expressed as: \[ v = \sqrt{\frac{8RT}{\pi M}} \] where: - \( R \) is the universal gas constant, - \( T \) is the absolute temperature, - \( M \) is the molar mass (molecular weight) of the gas. 3. **Setting Up the Ratio**: Since the volume and temperature are the same for both gases, we can compare the collision frequencies for helium and oxygen: \[ \frac{z_{He}}{z_{O_2}} = \frac{2 \sigma^2 n v_{He}}{2 \sigma^2 n v_{O_2}} = \frac{v_{He}}{v_{O_2}} \] 4. **Substituting Average Speeds**: Now substituting the expression for average speeds: \[ \frac{v_{He}}{v_{O_2}} = \frac{\sqrt{\frac{8RT}{\pi M_{He}}}}{\sqrt{\frac{8RT}{\pi M_{O_2}}}} = \sqrt{\frac{M_{O_2}}{M_{He}}} \] 5. **Using Molecular Weights**: The molecular weights are: - \( M_{He} = 4 \, \text{g/mol} \) - \( M_{O_2} = 32 \, \text{g/mol} \) Therefore: \[ \frac{z_{He}}{z_{O_2}} = \sqrt{\frac{32}{4}} = \sqrt{8} = 2\sqrt{2} \] 6. **Conclusion**: The ratio of the number of collisions per second at the walls of containers by helium and oxygen gas molecules is: \[ \frac{z_{He}}{z_{O_2}} = 2\sqrt{2} \] ### Final Answer: The ratio of the number of collisions per second at the walls of containers by He and O₂ gas molecules is \( 2\sqrt{2} \).
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