At what depth from the surface of the earth, the acceleration due to gravity will be `(1)/(4)` th the value of g on the surface of the earth ?

Explanation

To find the depth from the surface of the Earth at which the acceleration due to gravity is one-fourth the value of \( g \) on the surface, we can use the formula for the acceleration due to gravity at a depth \( d \):

\[ g' = g \left(1 - \frac{d}{R_e}\right) \]

where:
- \( g' \) is the acceleration due to gravity at depth \( d \),
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