Home
Class 12
PHYSICS
The acceleration due to gravity at a hei...

The acceleration due to gravity at a height 1 km above the earth is the same as at a depth d below the surface of earth. Then

A

`d = 1/2 km`

B

` d = 1 km`

C

`d = 3/2 km`

D

`d = 2 km `

Text Solution

Verified by Experts

The correct Answer is:
D
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • GRAVITATION

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT SECTION - D (ASSERTION-REASON TYPE QUESTIONS)|15 Videos

  • GRAVITATION

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT SECTION - B (OBJECTIVE TYPE QUESTIONS)|22 Videos

  • ELECTROSTATIC POTENTIAL AND CAPACITANCE

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT SECTION - D|9 Videos

  • KINETIC THEORY

    AAKASH INSTITUTE ENGLISH|Exercise EXERCISE (ASSIGNMENT) SECTION - D Assertion - Reason Type Questions|10 Videos

Similar Questions

Explore conceptually related problems

The acceleration due to gravity at a height 1km above the earth is the same as at a depth d below the surface of earth. Then :

The ratio of acceleration due to gravity at a height 3 R above earth's surface to the acceleration due to gravity on the surface of earth is (R = radius of earth)

The value of acceleration due to gravity at the surface of earth

The acceleration due to gravity at a depth R//2 below the surface of the earth is

If the change in the value of g at a height h above the surface of earth is the same as at a depth d below it (both h and d are much smaller than the radius of the earth), then

If the change in the value of g at a height h above the surface of earth is the same as at a depth d below it (both h and d are much smaller than the radius of the earth), then

Find the acceleration due to gravity at a point 64km below the surface of the earth. R = 6400 k, g on the surface of the earth = 9.8 ms^(-2) .

Calculate the value of acceleration due to gravity at a point a. 5.0 km above the earth's surface and b. 5.0 km below the earth's surface. Radius of earth =6400 km and the value of g at the surface of the earth is 9.80 ms^2

The acceleration due to gravity at the surface of the earth is g . The acceleration due to gravity at a height (1)/(100) times the radius of the earth above the surface is close to :

The density of a newly discovered planet is twice that of earth. The acceleration due to gravity at the surface of the planet is equal to that at the surface of the earth. If the radius of the earth is R , the radius of the planet would be

Home
Profile