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An open container has dimensions of 4.0 ...

An open container has dimensions of `4.0 m xx5.0 m ` and height of 3.0 m.
(i) Find the weight of the air in the container at `20^(@)C`.
(ii) What is the weight of an equal volume of water ? Also find pressure at the base of container due to this weight pof water.
(iii) What is the total downward force on the base of the container due to air pressure of 1.0 atm ?
Take the denities of air and water as `1.2 kg//m^(3)` and `10^(3) kg//m^(3)` respectively.

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Let's solve the problem step by step. ### Given Data: - Dimensions of the container: - Length (L) = 4.0 m - Width (W) = 5.0 m - Height (H) = 3.0 m - Density of air (ρ_air) = 1.2 kg/m³ ...
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