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The surface tension of a soap solution i...

The surface tension of a soap solution is `30 xx 10^(-3) N m^(-1)`. How much work is done to increase the radius of a soap bubble from 1.5 cm to 3 cm?

Text Solution

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Hence Surface tension , S = `30xx10^(-3) Nm^(-1)`
Initial radius = 1.5 cm = `1.5xx10^(-2)`cm
Final radius = 3 cm = `3xx10^(-2)`m
Work done = S `xx` Change in surface area
`Sxx2xx4pi(r_(2)^(2) - r_(1)^(2))`
`30xx10^(-3)xx2xxxxpi(9-2.25) xx10^(-4)`
`5.091xx10^(-4)J`
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