The freezing point of water on a thermometer is marked as 20unit and the boiling point as 120 unit. Find the value of temperature `80^(@)C` on this thermometer.

The freezing point on a thermometer is marked as -20^(@) and the boiling point as 130^(@) . A temperature of human body (34^(@)C) on this thermometer will be read as

A faulty thermometer reads 5^@ C melting ice and 99^@ C in steam. Find the correct temperature in ^@ C when this faulty thermometer reads 52^@ C .

Boiling point of water is defined as the temperature at which:

In a termperature scale X ice point of water is assigned a value of 20^(@) X and the boiling point of water is assiggned a value of 220^(@) X . In another scale Y the ice poiny of water is assigned a value of -20^(@) Y and the boiling point is given a value of 380^(@)Y . Then temperature on both the scales will be same is

The disjunction of the statement:"Freezing point of water is 0 ^o and Boiling point is 100 ^o ."

A faulty thermometer reads freezing point and boiling point of water as -5 ^(@)C abd 95^(@)C respectively . What is the correct value of temperature as it reads 60^(@)C on faulty thermometer?

The steam point and the ice point of a mercury thermometer are marked as 80^@ and 10^@ . At what temperature on centigrade scale the reading of this thermometer will be 59^@ ?

The steam point and the ice point of a mercury thermometer are marked as 80^@ and 10^@ . At what temperature on centigrade scale the reading of this thermometer will be 59^@ ?

The steam point and the ice point of a mercury thermometer are marked as 80^@C and 20^@C . What will be the temperature in centigrade mercury scale when this thermometer reads 32^@C ?

The steam point and the ice point of a Mercury thermometer are marked as 80^0 and 20^0 . What will be the temperature in centigrade mercury scale when this thermometer reads 32^0 ?