A particle executes a simple harmonic motion of time period T. Find the time taken by the particle to go directly from its mean position to half the amplitude.

Explanation

`x=A sin omegat `
`(A)/(2) = A sin omegat`
`sin. (pi)/(6) = sin. (2pi)/(T)t`
`(pi)/(6) = (2pi)/(T) t ` ` t = (T)/(12)`