Four charge are placed at the corners of a square of side 10 cm as shown in figure having. If q is `1 mu C`, then what will be electric field intensity at the centre of the square?

Explanation

Side = 0.1 m
Half of diagonal `=(a)/(sqrt(2))=(0.1)/(sqrt(2))`

Electric field due to charge q,
`=(9xx10^(9)xx1xx10^(-6))/(((0.1)/(sqrt(2)))^(2))=(9xx10^(3)xx2)/(0.01)=18xx10^(5)` N/C
At centre there are two electric field which are perpendicular to each other, so net electric field
`E_(0)=sqrt(E^(2)+E^(2))=Esqrt(2)=18xx10^(5)xx sqrt(2)=2.54xx10^(6)` N/C