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Statement - 1 : If a concentric spheeric...

Statement - 1 : If a concentric spheerical Gaussian surface is drawn inside thin spheical shell charge, electric field (E) at each point of surface must be zero.
Statement - 2 : In accordance with Gauss's law
`phi_(E)=oint vec(E).d vec(A)=(Q_("net enclosed"))/(epsilon_(0))`
`Q_("net enclosed")=0" implies "phi_(E)=0`

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To solve the problem, we need to analyze both statements provided in the question and determine their validity based on the principles of electrostatics and Gauss's law. ### Step-by-Step Solution: 1. **Understanding Statement 1**: - The first statement claims that if a concentric spherical Gaussian surface is drawn inside a thin spherical shell (which is uniformly charged), the electric field (E) at each point of the surface must be zero. - According to electrostatics, a charged spherical shell produces an electric field only outside the shell. Inside the shell, the electric field is indeed zero due to the symmetry of the charge distribution. Therefore, this statement is **true**. ...
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