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What is the amount of charge possessed b...

What is the amount of charge possessed by `1 kg` of electrons

A

`1.76xx10^(11)C`

B

`1.76xx10^(-9)` C

C

`1.76xx10^(-7)C`

D

`1.76xx10^(-5)` C

Text Solution

AI Generated Solution

The correct Answer is:
To find the amount of charge possessed by 1 kg of electrons, we can follow these steps: ### Step 1: Determine the charge of a single electron. The charge of one electron is approximately: \[ e = 1.6 \times 10^{-19} \text{ coulombs} \] ### Step 2: Determine the mass of a single electron. The mass of one electron is approximately: \[ m_e = 9.1 \times 10^{-31} \text{ kg} \] ### Step 3: Calculate the number of electrons in 1 kg. To find the number of electrons in 1 kg, we can use the formula: \[ \text{Number of electrons} = \frac{\text{Total mass}}{\text{Mass of one electron}} = \frac{1 \text{ kg}}{9.1 \times 10^{-31} \text{ kg}} \] Calculating this gives: \[ \text{Number of electrons} \approx \frac{1}{9.1 \times 10^{-31}} \approx 1.1 \times 10^{30} \] ### Step 4: Calculate the total charge of 1 kg of electrons. The total charge can be calculated by multiplying the number of electrons by the charge of one electron: \[ \text{Total charge} = \text{Number of electrons} \times \text{Charge of one electron} \] Substituting the values we have: \[ \text{Total charge} = (1.1 \times 10^{30}) \times (1.6 \times 10^{-19} \text{ C}) \] Calculating this gives: \[ \text{Total charge} \approx 1.76 \times 10^{11} \text{ C} \] ### Conclusion: Thus, the amount of charge possessed by 1 kg of electrons is approximately: \[ \text{Total charge} \approx 1.76 \times 10^{11} \text{ coulombs} \]
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