Home
Class 12
PHYSICS
A hemispherical surface of radius R is k...

A hemispherical surface of radius R is kept in a uniform electric field E as shown in figure. The flux through the curved surface is

A

`E2pi R^(2)`

B

`Epi R^(2)`

C

`E4pi R^(2)`

D

Zero

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Similar Questions

Explore conceptually related problems

The electric flux through the surface

The electric flux through the surface

The electric flux through the surface

A hemispherical body of radius R is placed in a uniform electric field E. What is the flux linked with the curved surface if, the field is (a) parallel to the base, (b) perpendicular to the base.

A hemispherical body of radius R is placed in a uniform electric field E. What is the flux linked with the curved surface if, the field is (a) parallel to the base, (b) perpendicular to the base.

If a hemispherical body is placed in a uniform electric field E then the flux linked with the curved surface is

A position charge Q is placed at a distance of 4R above the centre of a disc of radius R. The magnitude of flux through the disc is phi . Now a hemispherical shell of radius R is placed over the disc such that it forms a closed surface. The flux through the curved surface (taking direction of area vector along outward normal as positive), is -

Find out the flux through the curved surface of a hemisphere of radius R if it is placed in a uniform electric field E as shown in figure

A conic surface is placed in a uniform electric field E as shown in figure. Such that the field is perpendicular to the surface on the side AB. The base of the cone is of radius R, and the height of the cone is h. The angle of the cone is theta . Find the magnitude of the flux that enters the cone's curved surface from the left side. Do not count the outgoing flux (thetalt45^@) .

A charge 'Q' is placed at the centre of a hemispherical surface of radius 'R'. The flux of electric field due to charge 'Q' through the surface of hemisphere is