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Consider a series L-R circuit in which L...

Consider a series L-R circuit in which `L=(1)/(pi)H` and resistance `R = 100 Omega ` . When the circuit is connected to a.c. source 220 V, 50 H. Find the current drawn from the source.

Text Solution

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Impedance `Z = sqrt(R^2 + (omegaL)^2) = sqrt(R^2 + 4pi^2f^2L^2) =sqrt((100)^2 + (100)^2) = 100sqrt2Omega`
`X_L = 2pifL = 100Omega`
Hence `l_rms =(V_rms)/Z = 220 /(100sqrt2) = 1.1 sqrt2 A`.
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