Find the potential difference across resistance, capacitance and inductance in series LCR circuit where `L=2.0 H, C = 1 mu F and R = 100 Omega`. The applied emf has the form `V= 100 sqrt(2) sin (1000 t)`

Explanation

To find the potential difference across the resistance (R), capacitance (C), and inductance (L) in a series LCR circuit, we will follow these steps:

### Step 1: Identify the given parameters
- Inductance \( L = 2.0 \, \text{H} \)
- Capacitance \( C = 1 \, \mu\text{F} = 1 \times 10^{-6} \, \text{F} \)
- Resistance \( R = 100 \, \Omega \)
- Applied EMF \( V = 100\sqrt{2} \sin(1000t) \)

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