The primary winding of transformer has `500` turns whereas its secondary has `5000` turns. The primary is connected to an ac supply of `20V,50Hz`. The secondary will have an output of

Options

A. 200 V. 50 Hz
B. 2 V, 50 Hz
C. 200 V, 500 Hz
D. 2 V, 5 Hz

Answer

To solve the problem, we will use the transformer equation that relates the primary and secondary voltages to the number of turns in the primary and secondary windings.

### Step-by-Step Solution:

1. **Identify Given Values:**
- Number of turns in the primary winding (Np) = 500
- Number of turns in the secondary winding (Ns) = 5000
- Voltage across the primary winding (Vp) = 20V

2. **Write the Transformer Equation:**
The relationship between the primary and secondary voltages and the number of turns is given by the formula:
\[ \frac{V_s}{V_p} = \frac{N_s}{N_p} \]
where \(V_s\) is the secondary voltage and \(V_p\) is the primary voltage.

3. **Rearrange the Equation to Solve for \(V_s\):**
We can rearrange the equation to find the secondary voltage:
\[ V_s = \frac{N_s}{N_p} \times V_p \]

4. **Substitute the Known Values:**
Substitute the values of \(N_s\), \(N_p\), and \(V_p\) into the equation:
\[ V_s = \frac{5000}{500} \times 20V \]

5. **Calculate the Secondary Voltage:**
Simplifying the fraction:
\[ V_s = 10 \times 20V = 200V \]

6. **Conclusion:**
The output voltage at the secondary winding is \(200V\).

### Final Answer:
The secondary voltage \(V_s\) is **200V**.