A current of 5A is flowing at 220V in the primary coil of a transformer. If the voltage produced in the secondary coil is 2200V and 50% of power is lost, then the current in the secondary coil will be –

Options

A. 0.25 A
B. 0.5 A
C. 2.5 A
D. `5 A`

Answer

To solve the problem, we need to find the current in the secondary coil of the transformer given the primary current, primary voltage, secondary voltage, and the power loss.

### Step-by-Step Solution:

1. **Identify Given Values:**
- Primary current, \( I_P = 5 \, \text{A} \)
- Primary voltage, \( V_P = 220 \, \text{V} \)
- Secondary voltage, \( V_S = 2200 \, \text{V} \)
- Power loss = 50%, so the output power is half of the input power.

2. **Calculate Input Power:**
The input power \( P_P \) can be calculated using the formula:
\[ P_P = V_P \times I_P \]
Substituting the values:
\[ P_P = 220 \, \text{V} \times 5 \, \text{A} = 1100 \, \text{W} \]

3. **Calculate Output Power:**
Since 50% of the power is lost, the output power \( P_S \) is:
\[ P_S = 0.5 \times P_P = 0.5 \times 1100 \, \text{W} = 550 \, \text{W} \]

4. **Relate Output Power to Secondary Current:**
The output power can also be expressed in terms of secondary voltage and current:
\[ P_S = V_S \times I_S \]
Rearranging for \( I_S \):
\[ I_S = \frac{P_S}{V_S} \]

5. **Substituting the Values:**
Now substituting the values we have:
\[ I_S = \frac{550 \, \text{W}}{2200 \, \text{V}} = 0.25 \, \text{A} \]

6. **Conclusion:**
The current in the secondary coil is:
\[ I_S = 0.25 \, \text{A} \]

### Final Answer:
The current in the secondary coil is **0.25 A**.

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