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The time required for a 50 Hz sinusoidal...

The time required for a 50 Hz sinusoidal alternating current to changed its value from zero to the r.m.s. value

A

`1.5xx10^(-2)` S

B

`2.5xx10^(-3)` s

C

`10 ^(-1)` s

D

`10 ^(-6)` s

Text Solution

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The correct Answer is:
To find the time required for a 50 Hz sinusoidal alternating current to change its value from zero to the root mean square (r.m.s.) value, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the relationship between maximum current and r.m.s. value**: The r.m.s. value (I_rms) of a sinusoidal current is given by the formula: \[ I_{rms} = \frac{I_{max}}{\sqrt{2}} \] where \(I_{max}\) is the maximum amplitude of the current. 2. **Determine the angular frequency**: The angular frequency (\(\omega\)) is related to the frequency (f) by the formula: \[ \omega = 2\pi f \] Given that the frequency \(f = 50 \, \text{Hz}\), we can calculate \(\omega\): \[ \omega = 2\pi \times 50 = 100\pi \, \text{rad/s} \] 3. **Find the time to reach the r.m.s. value**: The current as a function of time for a sinusoidal wave can be expressed as: \[ I(t) = I_{max} \sin(\omega t) \] To find the time when the current reaches the r.m.s. value, we set: \[ I_{rms} = I_{max} \sin(\omega t) \] Substituting the expression for \(I_{rms}\): \[ \frac{I_{max}}{\sqrt{2}} = I_{max} \sin(\omega t) \] Dividing both sides by \(I_{max}\) (assuming \(I_{max} \neq 0\)): \[ \frac{1}{\sqrt{2}} = \sin(\omega t) \] 4. **Solve for \(\omega t\)**: The value of \(\sin(\theta) = \frac{1}{\sqrt{2}}\) corresponds to: \[ \theta = \frac{\pi}{4} \, \text{radians} \] Therefore, we have: \[ \omega t = \frac{\pi}{4} \] 5. **Calculate time (t)**: Now, we can solve for \(t\): \[ t = \frac{\pi/4}{\omega} \] Substituting \(\omega = 100\pi\): \[ t = \frac{\pi/4}{100\pi} = \frac{1}{400} \, \text{seconds} \] Simplifying this gives: \[ t = 0.0025 \, \text{seconds} = 2.5 \times 10^{-3} \, \text{seconds} \] ### Final Answer: The time required for a 50 Hz sinusoidal alternating current to change its value from zero to the r.m.s. value is: \[ t = 2.5 \times 10^{-3} \, \text{seconds} \]
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