Power factor of an ideal choke coil (i.e. R = 0) is

Options

A. Near about zero
B. Zero
C. Near about one
D. One

Answer

To find the power factor of an ideal choke coil, we can follow these steps:

### Step 1: Understand the Components of a Choke Coil
A choke coil primarily consists of inductance (L) and has a negligible resistance (R). In an ideal choke coil, we assume that the resistance R approaches zero.

### Step 2: Define Impedance
The impedance (Z) of a circuit is given by the formula:
\[ Z = \sqrt{R^2 + X_L^2} \]
where \( X_L \) is the inductive reactance, which can be expressed as:
\[ X_L = 2\pi f L \]
with \( f \) being the frequency of the alternating current.

### Step 3: Analyze the Impedance for an Ideal Choke Coil
Since we are considering an ideal choke coil, we have:
- \( R \approx 0 \)
- \( X_L \) is significantly larger than \( R \)

Thus, the impedance can be simplified to:
\[ Z \approx X_L \]

### Step 4: Calculate the Power Factor
The power factor (PF) is defined as the cosine of the phase angle (\( \phi \)) between the voltage and the current in an AC circuit. It can be expressed as:
\[ \text{Power Factor} = \cos \phi = \frac{R}{Z} \]

Substituting the values we have:
\[ \cos \phi = \frac{R}{Z} \]
Since \( R \approx 0 \) and \( Z \approx X_L \), we can write:
\[ \cos \phi = \frac{0}{X_L} = 0 \]

### Step 5: Conclusion
Therefore, the power factor of an ideal choke coil is:
\[ \text{Power Factor} = 0 \]