An Ac source is rated 222 V, 60 Hz. The average voltage is calculated in a time interval of 16.67 ms.IL

Options

A. Must be zero
B. May be zero
C. is never zero
D. Is `(111sqrt(2))` V

Answer

To solve the problem of calculating the average voltage of an AC source over a specific time interval, we can follow these steps:

### Step 1: Understand the AC Voltage
The AC source is rated at 222 V (RMS voltage) and operates at a frequency of 60 Hz. The RMS (Root Mean Square) voltage is the effective value of the AC voltage.

### Step 2: Calculate the Time Period
The time period (T) of the AC source can be calculated using the formula:
\[ T = \frac{1}{f} \]
where \( f \) is the frequency in Hertz (Hz).

Given:
- \( f = 60 \, \text{Hz} \)

Calculating the time period:
\[ T = \frac{1}{60} \approx 0.01667 \, \text{s} = 16.67 \, \text{ms} \]

### Step 3: Average Voltage Calculation
The average voltage over one complete cycle of a sinusoidal AC waveform is zero. This is because the positive half of the cycle cancels out the negative half.

Since the time interval given (16.67 ms) corresponds to one complete cycle of the AC waveform, the average voltage (V_avg) over this interval is:
\[ V_{\text{avg}} = 0 \, \text{V} \]

### Conclusion
The average voltage calculated over the time interval of 16.67 ms for the given AC source is:
\[ V_{\text{avg}} = 0 \, \text{V} \]

### Final Answer
The average voltage is 0 V.

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