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A convex surface of radius of curvature 40 cm separate two media of refractive indices `(4)/(3)` and 1.50. An object is kept in the first medium at a distance of 20 cm from the surface. Calculate the position of the image.

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`mu_(1)=4/3,mu_(2)=1.50,u=-20cm,R=40cm`
`mu_(2)/v-mu_(1)/u=(mu_(2)-mu_(1))/R`
`(1.50)/v-(4/3)/(-20cm)=(1.50-4/3)/(40cm)`
`rArrv=-24cm`
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