An equilateral glass prism is made of a material of refractive index 1.500. Find its angle of minimum deviation.

Explanation

`A=60^(@),mu=1.5,delta=?`
Substituting in `mu=("sin"(A+delta)/2)/("sin"A/2)`
`1.5=sin[(60^(@)+delta)/2]/sin[60/2]`
`1.5sin30^(@)=sin[(60^(@)+delta)/2]`
`sin[(60^(@)+delta)/2]=1.5xx0.5000=0.7500`
`(60^(@)+delta)/2=48^(@)35.,60^(@)+delta=97^(@)10.`
`rArrdelta=37^(@)10.`