What will be the deviation produced when a ray of light is incident on a plane mirror at an angle of incidence `60^(@)`?

Options

A. `30^(@)`
B. `90^(@)`
C. `60^(@)`
D. `120^(@)`

Answer

To find the deviation produced when a ray of light is incident on a plane mirror at an angle of incidence of \(60^\circ\), we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Setup**:
- Draw a diagram of a plane mirror.
- Indicate the incident ray making an angle of \(60^\circ\) with the normal to the mirror surface.

2. **Identify the Angle of Incidence**:
- The angle of incidence \(I\) is given as \(60^\circ\).

3. **Apply the Law of Reflection**:
- According to the law of reflection, the angle of reflection \(R\) is equal to the angle of incidence. Therefore, \(R = 60^\circ\).

4. **Determine the Total Angle**:
- The incident ray and the reflected ray form a straight line with the normal. The angles involved are:
- Angle of incidence \(I = 60^\circ\)
- Angle of reflection \(R = 60^\circ\)
- The sum of these angles and the deviation forms a straight line, which is \(180^\circ\).

5. **Calculate the Angle of Deviation**:
- The angle of deviation \(\delta\) can be calculated using the formula:
\[ \delta = 180^\circ - (I + R) \]
- Substituting the values:
\[ \delta = 180^\circ - (60^\circ + 60^\circ) = 180^\circ - 120^\circ = 60^\circ \]

6. **Conclusion**:
- The deviation produced when the ray of light is incident on the plane mirror at an angle of incidence of \(60^\circ\) is \(60^\circ\).

### Final Answer:
The deviation produced is \(60^\circ\).

---