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A light ray is incident normally on one ...

A light ray is incident normally on one of the refracting faces of a prism and just emerges out grazing the second surface. Then, the relation between angle of the prism and its critical angle is

A

A = C

B

`AneC`

C

`AltC`

D

`AgtC`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the situation described in the question step by step. ### Step 1: Understand the Geometry of the Prism We have a prism with an angle \( A \). A light ray is incident normally on one of the refracting faces of the prism. Since it is incident normally, the angle of incidence \( i_1 \) at this face is \( 0^\circ \). ### Step 2: Refraction at the First Face When the light ray enters the prism, it will refract according to Snell's law. However, since it is incident normally, the angle of refraction \( r_1 \) will also be \( 0^\circ \). Thus, the light ray travels inside the prism without bending. ### Step 3: Emergence from the Second Face The light ray will now reach the second face of the prism. As it travels through the prism, it will eventually reach the point where it just grazes the second surface. When a light ray grazes a surface, it means that the angle of refraction at that point is \( 90^\circ \). ### Step 4: Applying the Critical Angle Concept The critical angle \( C \) is defined as the angle of incidence at which the angle of refraction is \( 90^\circ \). For the light ray to just graze the second surface, the angle of incidence \( i_2 \) at the second face must equal the critical angle \( C \). ### Step 5: Relating the Angles From the geometry of the prism, we know that the angle of incidence \( i_2 \) at the second face can be expressed in terms of the angle of the prism \( A \) and the critical angle \( C \). Since the light ray travels through the prism, the relationship can be given as: \[ i_2 + A = 90^\circ \] Thus, we can express the critical angle as: \[ C = 90^\circ - A \] ### Step 6: Final Relation Since we have established that the angle of incidence at the second face is equal to the critical angle, we can set: \[ C = A \] Thus, the relation between the angle of the prism \( A \) and its critical angle \( C \) is: \[ A = C \] ### Conclusion The relation between the angle of the prism and its critical angle is: \[ \text{Angle of the prism } A = \text{Critical angle } C \]
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AAKASH INSTITUTE ENGLISH-RAY OPTICS AND OPTICAL INSTRUMENTS-EXERCISE
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  2. A lens made of material of Refractive index mu(2) is surrounded by a m...

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  3. A light ray is incident normally on one of the refracting faces of a p...

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  4. If a light ray incidents normally on one of the faces of the prism of ...

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  5. A ray of light is incident on one of the faces of the angle prism with...

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  6. A prism of refractive index sqrt2 has refractive angle 60^@. In the or...

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  7. The least angle of deviation for a glass prism is equal to its refract...

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  8. A light ray of angles of incidence 40^(@) emerged from the prism in mi...

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  9. The angle of minimum deviation for a 75^(@) prism of dense glass is fo...

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  10. Suppose a small angled prism of 6^(@) deviates a ray through 3^(@), th...

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  11. For a given prism thetaanddelta are angular dispersion and deviation. ...

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  12. If a is the size of scatterer and lamda is the wavelength of light the...

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  13. Which of the following colour is scattered most is atmosphere?

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  15. Lateral magnification of objective of compound microscope is 100 and a...

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  16. Focal length of objective eye piece and inverting lens of a terrestria...

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  17. Advantages of cassegrain telescope is/are

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  18. A simple telescope consisting of an objective of focal length 60 cm an...

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  19. A telescope has an objective lens of focal length 200cm and an eye pie...

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  20. Which of the following is not involved in Rainbow formation?

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