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A lens of refractive index mu is put in ...

A lens of refractive index `mu` is put in a liquid of refractive index `mu'`. If focal length of lens in air is `f`, its focal length in liquid will be.

A

`(fmu'(mu-1))/((mu-mu'))`

B

`(f(mu'-mu))/(mu'(mu-1))`

C

`(mu'(mu-1))/(f(mu'-mu))`

D

`(fmumu')/((mu-mu'))`

Text Solution

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The correct Answer is:
A
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