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A beam of light of wavelength 400 nm fal...

A beam of light of wavelength 400 nm falls on a narrow slit and the resulting diffraction pattern is observed on a screen 2 m away from the slit. It is observed that 2nd order minima occurs at a distance of 2 mm from the position of central maxima. Find the width of the slit.

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Now poitn Q is the point of second order minima.
Now `sin theta=tan theta= theta=(2 tunes 10^-3)/2=10^-3`
Let the slit separation be a.
Now for second order minima `theta=(2lamda)/a`
Equating `(2lamda)/a` by `theta=10^-3` we obtain a=0.8 nm.
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