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Two light waves having the same waveleng...

Two light waves having the same wavelengths `lambda` in vacuum are in phase initially . Then the first wave travels a path `L_1` through a medium of refractive index `n_1` while the second wave travels a path of length `L_2` through a medium of refractive index `n_2` . After this the phase difference between the two waves is :

A

`(2pi)/lamda(L_2-L_1)`

B

`(2pi)/lamda(n_1 L_1-n_2 L_2)`

C

`(2pi)/lamda(n_2L_1+n_1L_2)`

D

`(2n)/lamda_1(L_1/n_1+L_2/n_2)`

Text Solution

Verified by Experts

Effective path length in air is nL and `phi=(2pi Delta)/lamda`
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