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In YDSE the distance between the slits i...

In YDSE the distance between the slits is 1mm and screen is 25nm away from intensities IF the wavelength of light is 6000A the fringe width on the screen is

A

0.15mm

B

0.30mm

C

0.24mm

D

0.12 mm

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To solve the problem of finding the fringe width in Young's Double Slit Experiment (YDSE), we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Given Values:** - Distance between the slits (d) = 1 mm = \(1 \times 10^{-3}\) m - Distance from the slits to the screen (D) = 25 nm = \(25 \times 10^{-9}\) m - Wavelength of light (λ) = 6000 Å = \(6000 \times 10^{-10}\) m ...
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