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A: The resolving power of a telescope de...

A: The resolving power of a telescope decreases on decreasing the aperture of its objective lens.
R: The resolving power of a telescope is given as `D/(1.22 lamda)` where D is aperture of the objective and `lamda` is the wavelength of light.

A

IF both Assertion & Reason are true and the reason is the correct explanation of the assertion, then mark (1).

B

If both Assertion & Reason are true but the reason is not the correct explanation of the assertion, then mark(2)

C

IF Assertion is true statement but Reason is false then mark(3)

D

If both Assertion and Reason are false statements, then mark (4)

Text Solution

AI Generated Solution

The correct Answer is:
To solve the assertion and reason question, we will analyze both the assertion (A) and the reason (R) step by step. ### Step 1: Understand the Assertion The assertion states that "the resolving power of a telescope decreases on decreasing the aperture of its objective lens." **Explanation:** - The resolving power of a telescope refers to its ability to distinguish between two closely spaced objects. A higher resolving power means that the telescope can distinguish finer details. - The aperture of the objective lens is the diameter of the lens through which light enters the telescope. A larger aperture allows more light to enter and improves the telescope's ability to resolve details. ### Step 2: Understand the Reason The reason states that "the resolving power of a telescope is given as D/(1.22 λ)," where D is the aperture of the objective and λ is the wavelength of light. **Explanation:** - The formula for resolving power (RP) is given by \( RP = \frac{D}{1.22 \lambda} \). - Here, D is directly proportional to the resolving power. This means that as D increases, the resolving power increases, and conversely, as D decreases, the resolving power decreases. ### Step 3: Analyze the Relationship From the formula \( RP = \frac{D}{1.22 \lambda} \): - If the aperture D decreases, the value of the resolving power RP will also decrease, since λ (wavelength) remains constant for a given light source. ### Step 4: Conclusion Both the assertion and the reason are true: - The assertion is true because decreasing the aperture leads to a decrease in resolving power. - The reason is also true as it correctly describes the relationship between the aperture and the resolving power. ### Final Answer Both the assertion (A) and the reason (R) are true, and the reason correctly explains the assertion.
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