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Light of wavelength 2000 Å falls on a metallic surface whose work function is 4.21 eV. Calculate the stopping potential

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` eV_(s) = (hc)/(lambda) - phi_(0) or V_(s) = (hc)/(e lambda) - (phi_(0))/(e) `
` V_(s) = (6.62 xx 10^(-34) xx 3 xx 10^(4))/( 1.6 xx 10^(-19) xx 2000 xx 10^(-10)) - 4.21 `
or ` V_(s) = 6.21 - 4.21 = 2 V `
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