Home
Class 12
PHYSICS
When light of wavelangth 4000 Å is incid...

When light of wavelangth `4000 Å` is incident on a barium emitter , emitted photo electrons in a transverse magnetic field strength ` B = 5.2 xx 10^(-6)` T moves in a circular path . Find the radius of the circle . Given work function of barium is 2.5 eV and mass of electron is ` 9.1 xx 10^(-31)` kg .
` e = 1.6 xx 10^(-19) C , h = 6.6 xx 10^(34) Js ` .

Text Solution

AI Generated Solution

To solve the problem, we will follow these steps: ### Step 1: Calculate the maximum kinetic energy of the emitted photoelectrons The maximum kinetic energy (K.E.) of the emitted photoelectrons can be calculated using the equation: \[ K.E. = E_{photon} - \phi \] ...
Promotional Banner

Topper's Solved these Questions

  • ALTERNATING CURRENT

    AAKASH INSTITUTE ENGLISH|Exercise Try Yourself|15 Videos

  • ALTERNATING CURRENT

    AAKASH INSTITUTE ENGLISH|Exercise Assignment (Section - A) ( Objective Type Questions ( One option is correct))|40 Videos

  • ATOMS

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT SECTION J (Aakash Challengers )|5 Videos

Similar Questions

Explore conceptually related problems

Calculate the energy in MeV equivalent to the rest mass of an electron . Given that the rest mass of an electron , m=9.1 xx 10^(-31) kg , 1MeV = 1.6 xx 10^(-13) J and speed of light , c= 3 xx 10 ^(8) ms ^(-1) .

The mass of an electron is 9. 1 xx 10^(-31) kg . If its K.E. is 3. 0 xx 10 ^(25) J . Calculate its wavelength .

In a photocell bichromatic light of wavelength 2475 Å and 6000 Å are incident on cathode whose work function is 4.8 eV . If a uniform magnetic field of 3 xx 10^(-5) Tesla exists parallel to the plate , the radius of the path describe by the photoelectron will be (mass of electron = 9 xx 10^(-31) kg )

An electron beam has a kinetic energy equal to 100 eV . Find its wavelength associated with a beam , if mass of electron = 9.1 xx 10^(-31) " kg and 1 eV " = 1.6 xx 10^(-19) J . (Planks's constant = 6.6 xx 10^(-34) J-s)

Molar mass of electron is nearly : (N_(A) = 6 xx 10^(23)) , mass of e^(-) = 9.1 xx 10^(-31)Kg

Light of wavelength 4000Å is incident on barium. Photoelectrons emitted describe a circle of radius 50 cm by a magnetic field of flux density 5.26xx10^-6 tesla . What is the work function of barium in eV? Given h=6.6xx10^(-34)Js , e=1.6xx10^(-19)C, m_e=9.1xx10^(-31)kg.

The speed of the electron in the hydrogen atom is approximately 2.2 xx 10^(6) m//s . What is the centripetal force acting on the electron ifthe radius of the circular orbit is 0.53 xx 10^(-10) m ?Mass of the electron is 9.1 xx 10^(-31) kg

If an electron is moving in a magnetic field of 5.4 xx 10^(-4)T on a circular path of radius 32 cm having a frequency of 2.5 MHz, then its speed will be

An electron is accelerated under a potential difference of 64 V, the de-Brogile wavelength associated with electron is [e = -1.6 xx 10^(-19) C, m_(e) = 9.1 xx 10^(-31)kg, h = 6.623 xx 10^(-34) Js]

If de Broglie wavelength of an electron is 0.5467 Å, find the kinetic energy of electron in eV. Given h=6.6xx10^(-34) Js , e= 1.6xx10^(-19) C, m_e=9.11xx10^(-31) kg.