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A proton and an alpha - particle are acc...

A proton and an alpha - particle are accelerated through same potential difference. Then, the ratio of de-Broglie wavelength of proton and alpha-particle is

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` lambda = (h)/(sqrt(2mQV))`
` rArr lambda oo (1)/(sqrt(mQ))`
` rArr (lambda_(p))/(lambda_(alpha)) = sqrt((m_(alpha) Q_(alpha))/(m_(p) xx Q_(p)))`
` = sqrt((4m_(p)xx 2Q_(p))/(m_(p) xx Q_(p)))`
` = 2sqrt(2)` .
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