Home
Class 12
PHYSICS
An electron of mass me and a proton of m...

An electron of mass `m_e` and a proton of mass `m_p` are accelerated through the same potential difference. The ratio of the de Broglie wavelength associated with an electron to that associated with proton is

A

2

B

`sqrt(2)`

C

4

D

`(1)/(2sqrt(2))`

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Topper's Solved these Questions

  • ALTERNATING CURRENT

    AAKASH INSTITUTE ENGLISH|Exercise Try Yourself|15 Videos

  • ALTERNATING CURRENT

    AAKASH INSTITUTE ENGLISH|Exercise Assignment (Section - A) ( Objective Type Questions ( One option is correct))|40 Videos

  • ATOMS

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT SECTION J (Aakash Challengers )|5 Videos

Similar Questions

Explore conceptually related problems

An electron and a proton are accelerated through the same potential difference. The ratio of their de broglic wavelengths will be

An electron is accelerated through a potential difference of V volit .Find th e de Broglie wavelength associated with electron.

A proton and deuteron are accelerated by same potential difference.Find the ratio of their de-Broglie wavelengths.

An alpha -particle and a proton are accelerated from rest through the same potential difference V. Find the ratio of de-Broglie wavelength associated with them.

An electron is accelerated by a potential difference of 50 V. Find the de Broglie wavelength associated with it.

An electron is accelerated by a potential difference of 25 V. Find the de Broglie wavelength associated with it.

A proton and an alpha - particle are accelerated through same potential difference. Then, the ratio of de-Broglie wavelength of proton and alpha-particle is

A proton and an alpha - particle are accelerated through same potential difference. Then, the ratio of de-Broglie wavelength of proton and alpha-particle is

An electron is accelerated by a potential difference of 9.375 V . Find the de-Broglie wavelength associated with it is Å

An alpha-"particle" is accelerated through a potential difference of V volts from rest. The de-Broglie's wavelengths associated with it is.