Home
Class 12
PHYSICS
The wavelength of a 1 keV photon is 1.24...

The wavelength of a `1 keV` photon is `1.24 xx 10^(-9)`m. What is the frequency of `1 MeV photon`?

A

` 1.24 xx 10^(15)` Hz

B

`2.4 xx 10^(20) Hz `

C

`1.24 xx 10^(18) Hz `

D

` 2.4 xx 10^(23) Hz `

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Topper's Solved these Questions

  • ALTERNATING CURRENT

    AAKASH INSTITUTE ENGLISH|Exercise Try Yourself|15 Videos
  • ALTERNATING CURRENT

    AAKASH INSTITUTE ENGLISH|Exercise Assignment (Section - A) ( Objective Type Questions ( One option is correct))|40 Videos
  • ATOMS

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT SECTION J (Aakash Challengers )|5 Videos

Similar Questions

Explore conceptually related problems

Wavelength of a 1 ke V photon is 1.24 xx 10^(-9) m . What is the frequency of 1 Me V photon ?

If λ= 9.7xx10^-8m , what is frequency of photon ?

The momentum of a photon is 33 xx 10^(- 29) kg - m//sec . Its frequency will be

If wavelength of photon is 2.2 xx 10^(-11)m , h = 6.6 xx 10^(-34) Js , then momentum of photons is

If wavelength of photon is 2.2× 10 ^(−9) m, h=6.6× 10 ^(−34) Jsec, then momentum of photon is

What is the wavelength of a photon of energy 1 eV?

If wavelength of photon is 1.1× 10 ^(−11) m, h=6.6× 10 ^(−34) Jsec, then momentum of photon is

If wavelength of photon is 1.1× 10 ^(−18) m, h=6.6× 10 ^(−34) Jsec, then momentum of photon is

If wavelength of photon is 2.2× 10 ^(−17) m, h=6.6× 10 ^(−34) Jsec, then momentum of photon is

The wavelength of a photon is 1.4 Å. It collides with an electron. The energy of the scattered electron is 4.26xx10^(-16) J. Find the wavelength of photon after collision.