Home
Class 12
PHYSICS
A photoelectric surface is illuminated s...

A photoelectric surface is illuminated successively by monochromatic light of wavelength `lambda` and `lambda/2`. If the maximum kinetic energy of the emitted photoelectrons in the second case is `3` times that in the first case, the work function of the surface of the material is (h = Planck's constant, c= speed of light)

A

`(hc)/(3 lambda)`

B

`(hc)/(2 lambda) `

C

`(hc)/(lambda) `

D

`(2 hc )/(lambda)`

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Topper's Solved these Questions

  • ALTERNATING CURRENT

    AAKASH INSTITUTE ENGLISH|Exercise Try Yourself|15 Videos
  • ALTERNATING CURRENT

    AAKASH INSTITUTE ENGLISH|Exercise Assignment (Section - A) ( Objective Type Questions ( One option is correct))|40 Videos
  • ATOMS

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT SECTION J (Aakash Challengers )|5 Videos

Similar Questions

Explore conceptually related problems

A photoelectric surface is illuminated successively by monochromatic light of wavelength lambda and (lambda)/(2) . If the maximum kinetic energy of the emitted photoelectrons in the second case is 3 times than in the first case , the work function of the surface of the material is ( h = Plank's constant , c = speed of light )

A photoelectric surface is illuminated successively by monochromatic light of wavelength lambda and (lambda)/(2) . If the maximum kinetic energy of the emitted photoelectrons in the second case is 3 times than in the first case , the work function of the surface of the material is ( h = Plank's constant , c = speed of light )

Light of wavelength 4000A∘ is incident on a metal surface. The maximum kinetic energy of emitted photoelectron is 2 eV. What is the work function of the metal surface?

When a metal surface is illuminated by light wavelengths 400 nm and 250 nm , the maximum velocities of the photoelectrons ejected are upsilon and 2 v respectively . The work function of the metal is ( h = "Planck's constant" , c = "velocity of light in air" )

Find the maximum kinetic energy of the photoelectrons ejected when light of wavelength 350nm is incident on a cesium surface. Work function of cesium = 1.9 e V.

A metallic surface is illuminated alternatively with light of wavelenghts 3000 Å and 6000 Å . It is observed that the maximum speeds of the photoelectrons under these illuminations are in the ratio 3 : 1 . Calculate the work function of the metal and the maximum speed of the photoelectrons in two cases.

A photonsensitive metallic surface is illuminated alternately with light of wavelength 3100 Å and 6200 Å . It is observed that maximum speeds of the photoelectrons in two cases are in ratio 2 : 1 . The work function of the metal is (hc = 12400 e VÅ)

A light of wavelength 600 nm is incident on a metal surface. When light of wavelength 400 nm is incident, the maximum kinetic energy of the emitted photoelectrons is doubled. The work function of the metals is

When a metallic surface is illuminated with monochromatic light of wavelength lambda , the stopping potential is 5 V_0 . When the same surface is illuminated with light of wavelength 3lambda , the stopping potential is V_0 . Then the work function of the metallic surface is:

The maximum velocity of an electron emitted by light of wavelength lambda incident on the surface of a metal of work function phi , is Where h = Planck's constant , m = mass of electron and c = speed of light.