Home
Class 12
PHYSICS
The work function of tungsten is 4.50 eV...

The work function of tungsten is 4.50 eV . The wavelength of fastest electron emitted when light whose photon energy is 5.50 eV falls on tungsten surface, is

A

12.27 Å

B

0.286 Å

C

12400 Å

D

1.227 Å

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Topper's Solved these Questions

  • ALTERNATING CURRENT

    AAKASH INSTITUTE ENGLISH|Exercise Try Yourself|15 Videos
  • ALTERNATING CURRENT

    AAKASH INSTITUTE ENGLISH|Exercise Assignment (Section - A) ( Objective Type Questions ( One option is correct))|40 Videos
  • ATOMS

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT SECTION J (Aakash Challengers )|5 Videos

Similar Questions

Explore conceptually related problems

The work function of a metallic surface is 5.01 eV . The photo - electrons are emitted when light of wavelength 2000 Å falls on it . The potential difference applied to stop the fastest photo - electrons is [ h = 4.14 xx 10^(-15) eV sec]

The work function of a metallic surface is 5.01 eV. The photoelectrons are emitted when light of wavelength 2000A falls on it. The potential difference applied to stop the fastest photoelectrons is

Work function of Sodium is 2.75eV. What will be KE of emitted electron when photon of energy 3.54eV is incident on the surface of sodium?

The work function of a metal is 4.2 eV . If radiation of 2000 Å fall on the metal then the kinetic energy of the fastest photoelectron is

The work function of a metal is 3.4 eV. A light of wavelength 3000Å is incident on it. The maximum kinetic energy of the ejected electron will be :

The work function for a metal is 4 eV. To eject the photo electrons with zero velocity the wavelength of the incident light should be

The maximum kinetic energy of photoelectrons emitted from a surface when photons of energy 6 eV fall on it is 4 eV . The stopping potential , in volt is

The stopping potential for the photoelectrons emitted from a metal surface of work function 1.7 eV is 10.4 V. Find the wavelength of the radiation used. Also, identify the energy levels in hydrogen atom, which will emit this wavelength.

The photoelectric work - function of potassium is 2.3 eV. If light having a wavelength of 2800 Å falls on potassium, find (a) the kinetic energy in electron volts of the most energetic electrons ejected. (b) the stopping potential in volts.

The work function of a metal is 2.4 eV. If radiations of 3000 A^o on the metal, then the kinetic energy of the fastest photoelectron is: