Light of wavelength `3000Å` is incident on a metal surface whose work function is 1 eV. The maximum velocity of emitted photoelectron will be

Explanation

To find the maximum velocity of the emitted photoelectron when light of wavelength \(3000 \, \text{Å}\) is incident on a metal surface with a work function of \(1 \, \text{eV}\), we can use Einstein's photoelectric equation:

\[ E = \phi + KE_{\text{max}} \]

where:
- \(E\) is the energy of the incident light,
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