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For intensity I of a light of wavelength...

For intensity `I` of a light of wavelength `5000 Å` the photoelectron saturation current is `0.40 mu A` and stopping potential is `1.36 V` , the work function of metal is

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To find the work function of the metal given the intensity of light, wavelength, photoelectron saturation current, and stopping potential, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Given Values:** - Wavelength, \( \lambda = 5000 \, \text{Å} = 5000 \times 10^{-10} \, \text{m} \) - Stopping potential, \( V_0 = 1.36 \, \text{V} \) - Photoelectron saturation current is not needed for the calculation of work function directly. ...
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