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As the n (number of orbit) increases, th...

As the n (number of orbit) increases, the difference of energy between the consecutive energy levels

A

Remain the same

B

Increases

C

Decreases

D

Sometimes increases and sometimes decreases

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question regarding how the difference of energy between consecutive energy levels changes as the principal quantum number \( n \) increases, we will follow these steps: ### Step 1: Understand the Energy Formula The energy of an electron in the nth orbit of a hydrogen-like atom is given by the formula: \[ E_n = -\frac{13.6 Z^2}{n^2} \text{ eV} \] where \( Z \) is the atomic number (for hydrogen, \( Z = 1 \)). ### Step 2: Calculate Energy Levels We will calculate the energy for the first four energy levels (orbits) using the formula. - For \( n = 1 \): \[ E_1 = -\frac{13.6 \times 1^2}{1^2} = -13.6 \text{ eV} \] - For \( n = 2 \): \[ E_2 = -\frac{13.6 \times 1^2}{2^2} = -\frac{13.6}{4} = -3.4 \text{ eV} \] - For \( n = 3 \): \[ E_3 = -\frac{13.6 \times 1^2}{3^2} = -\frac{13.6}{9} \approx -1.51 \text{ eV} \] - For \( n = 4 \): \[ E_4 = -\frac{13.6 \times 1^2}{4^2} = -\frac{13.6}{16} \approx -0.85 \text{ eV} \] ### Step 3: Calculate Differences in Energy Levels Now, we will calculate the differences in energy between consecutive levels: - Difference between \( E_1 \) and \( E_2 \): \[ \Delta E_{1 \to 2} = E_2 - E_1 = -3.4 - (-13.6) = 10.2 \text{ eV} \] - Difference between \( E_2 \) and \( E_3 \): \[ \Delta E_{2 \to 3} = E_3 - E_2 = -1.51 - (-3.4) \approx 1.89 \text{ eV} \] - Difference between \( E_3 \) and \( E_4 \): \[ \Delta E_{3 \to 4} = E_4 - E_3 = -0.85 - (-1.51) \approx 0.66 \text{ eV} \] ### Step 4: Analyze the Differences From the calculations: - \( \Delta E_{1 \to 2} = 10.2 \text{ eV} \) - \( \Delta E_{2 \to 3} \approx 1.89 \text{ eV} \) - \( \Delta E_{3 \to 4} \approx 0.66 \text{ eV} \) As \( n \) increases, the differences in energy between consecutive levels decrease. ### Conclusion Thus, as the principal quantum number \( n \) increases, the difference of energy between consecutive energy levels decreases. ### Final Answer The correct answer is that the difference of energy between consecutive energy levels decreases as \( n \) increases. ---
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