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Total energy of an electron in the hydro...

Total energy of an electron in the hydrogen atom in the ground state is -13.6 eV. The potential energy of this electron is

A

`13.6 eV`

B

Zero

C

`-27.2 eV`

D

`-13.6 eV`

Text Solution

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The correct Answer is:
To find the potential energy of an electron in a hydrogen atom in the ground state, we can use the relationship between total energy, kinetic energy, and potential energy. Here’s a step-by-step solution: ### Step 1: Understand the relationship between total energy, kinetic energy, and potential energy. The total energy (E) of an electron in a hydrogen atom is given by the equation: \[ E = K + U \] where \( K \) is the kinetic energy and \( U \) is the potential energy. ### Step 2: Use the known values. From the question, we know that the total energy in the ground state of the hydrogen atom is: \[ E = -13.6 \, \text{eV} \] ### Step 3: Relate potential energy and kinetic energy. In a hydrogen atom, the potential energy is related to the kinetic energy by the equation: \[ U = -2K \] ### Step 4: Express kinetic energy in terms of total energy. Since we have \( E = K + U \) and \( U = -2K \), we can substitute \( U \) into the total energy equation: \[ E = K - 2K = -K \] This implies: \[ K = -E \] ### Step 5: Substitute the value of total energy to find kinetic energy. Substituting the value of total energy: \[ K = -(-13.6 \, \text{eV}) = 13.6 \, \text{eV} \] ### Step 6: Calculate potential energy using kinetic energy. Now, we can find the potential energy using the relationship \( U = -2K \): \[ U = -2 \times 13.6 \, \text{eV} = -27.2 \, \text{eV} \] ### Conclusion: The potential energy of the electron in the hydrogen atom in the ground state is: \[ U = -27.2 \, \text{eV} \]
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