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Consider 3^(rd) orbit of He^(+) (Helium)...

Consider `3^(rd)` orbit of `He^(+)` (Helium), using non-relativistic approach, the speed of electron in this orbit will be (given `K=9xx10^(9)` constant, Z=2 and h (Planck's constant) `=6.6xx10^(-34)J-s)`

A

`3.0 xx 10^(8) m/s`

B

`2.92 xx 10^(6) m/s`

C

`1.46 xx 10^(6) m/s`

D

`0.73 xx 10^(6) m/s`

Text Solution

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The correct Answer is:
C
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