What would be the energy of activation for a reaction when a change of temperature from `20^@C " to " 30^@C` exactly triples the reaction rate constant ?

Explanation

To find the energy of activation (Ea) for a reaction when the temperature changes from 20°C to 30°C and the reaction rate constant triples, we can use the Arrhenius equation. Here’s a step-by-step solution:

### Step 1: Understand the Problem
We are given:
- Initial temperature (T1) = 20°C = 293 K (after converting to Kelvin)
- Final temperature (T2) = 30°C = 303 K (after converting to Kelvin)
- The rate constant at T1 is K and at T2 is 3K.

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