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The activation energy of a reaction is 9...

The activation energy of a reaction is `94.14 kJ mol^(-1)` and the value of rate constant at `313 K` is `18 xx 10^(-5) s^(-1)`. Calculate the frequency factor or pre-exponential factor, `A`.

Text Solution

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`E_a=94.14" kJ mol"^(-1)=94140" J mol"^(-1)`
`T=313"K k" = 1.8xx10^(-5)s^(-1)`
`logk=E_a/(2.303RT)+logA`
`logA=log1.8xx10^(-5)+94140/(2.303xx8.314xx313)`
`A = 9.194xx10^(10)` collisions
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