Two waves represented by `y=a" "sin(omegat-kx) and y=a" " sin(omega-kx+(2pi)/(3))` are superposed. What will be the amplitude of the resultant wave?

Explanation

To find the amplitude of the resultant wave when two waves are superposed, we can follow these steps:

### Step 1: Identify the wave equations
We have two waves given by:
1. \( y_1 = a \sin(\omega t - kx) \)
2. \( y_2 = a \sin(\omega t - kx + \frac{2\pi}{3}) \)

### Step 2: Determine the phase difference
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