A man fires a gun while standing between two parallel hills. If he hears the first echo after 2 s and the second echo 3 s after the first echo, then calculate the distance between the hills the velocity of sound is 330 m/s.

Answer

1155 m

Explanation

`y_(1)+y_(2)=((v xx t_1)/(2)) + ( v xx t._2)/(2))`. Where ` t._2 = t_1 + t_2 = 2 +3 =5s `