The wavelength of sound waves in hydrogen gas corresponding to the lower limit of audibility is ( speed of sound in hydrogen gas is about 1350 m/s) .

Options

A. 60 m
B. 67.5 m
C. 100 m
D. 500 m

Answer

To find the wavelength of sound waves in hydrogen gas corresponding to the lower limit of audibility, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Speed of Sound**:
The speed of sound in hydrogen gas is given as \( v = 1350 \, \text{m/s} \).

2. **Determine the Lower Limit of Audibility**:
The lower limit of audibility for humans is \( f = 20 \, \text{Hz} \).

3. **Use the Wavelength Formula**:
The formula to calculate the wavelength \( \lambda \) is:
\[ \lambda = \frac{v}{f} \]
where \( v \) is the speed of sound and \( f \) is the frequency.

4. **Substitute the Values**:
Now, substitute the values of speed and frequency into the formula:
\[ \lambda = \frac{1350 \, \text{m/s}}{20 \, \text{Hz}} \]

5. **Calculate the Wavelength**:
Performing the division:
\[ \lambda = \frac{1350}{20} = 67.5 \, \text{m} \]

6. **Final Result**:
Thus, the wavelength of sound waves in hydrogen gas corresponding to the lower limit of audibility is \( \lambda = 67.5 \, \text{m} \).