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Which one of the following represents a...

Which one of the following represents a wave ?

A

`y= A sin ( omega t- kx)`

B

`y=A cos^(2)(at-bx+c) +A sin^(2) (at-bx+c)`

C

`y=A sin kx `

D

`y=Asin omega t `

Text Solution

AI Generated Solution

The correct Answer is:
To determine which of the given options represents a wave, we can use the wave equation, which is given by: \[ \frac{\partial^2 y}{\partial t^2} = c^2 \frac{\partial^2 y}{\partial x^2} \] where \(y\) is the displacement, \(t\) is time, \(x\) is position, and \(c\) is the speed of the wave. Let's analyze each option step by step: ### Step 1: Analyze Option A Assume the form of the wave is given by: \[ y = A \sin(\omega t - kx) \] 1. **Calculate \(\frac{\partial^2 y}{\partial t^2}\)**: - First derivative: \[ \frac{\partial y}{\partial t} = A \omega \cos(\omega t - kx) \] - Second derivative: \[ \frac{\partial^2 y}{\partial t^2} = -A \omega^2 \sin(\omega t - kx) \] 2. **Calculate \(\frac{\partial^2 y}{\partial x^2}\)**: - First derivative: \[ \frac{\partial y}{\partial x} = -A k \cos(\omega t - kx) \] - Second derivative: \[ \frac{\partial^2 y}{\partial x^2} = -A k^2 \sin(\omega t - kx) \] 3. **Substitute into the wave equation**: - LHS: \[ -A \omega^2 \sin(\omega t - kx) \] - RHS: \[ c^2 (-A k^2 \sin(\omega t - kx)) \] - Setting LHS = RHS gives: \[ A \omega^2 = c^2 A k^2 \implies \frac{\omega^2}{k^2} = c^2 \implies c = \frac{\omega}{k} \] - This satisfies the wave equation. ### Step 2: Analyze Option B Assume: \[ y = A \cos^2(\theta) + A \sin^2(\theta) \] Using the identity \(\cos^2(\theta) + \sin^2(\theta) = 1\): \[ y = A \] - This is a constant and does not vary with time or position, hence it does not represent a wave. ### Step 3: Analyze Option C Assume: \[ y = A \] - This is also a constant value and does not depend on time or position, hence it does not represent a wave. ### Step 4: Analyze Option D Assume: \[ y = 0 \] - This is a trivial case where there is no displacement at all, hence it does not represent a wave. ### Conclusion After analyzing all options, we find that only **Option A** satisfies the wave equation and represents a wave. ### Final Answer The correct option that represents a wave is **Option A**. ---
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