Home
Class 12
PHYSICS
If f(1) and f(2) be the fundamental freq...

If `f_(1) and f_(2)` be the fundamental frequencies of the two segments into which a stretched string is divided by means of a bridge , then find the original fundamental frequency `f` of the complete string.

A

`(f_1f_2)/(f_1+f_2) = f`

B

`2f=f_1 +f_2`

C

`sqrt(f)=sqrt(f_1)+sqrt(f_2)`

D

`sqrt(f_1+f_2)=2f`

Text Solution

AI Generated Solution

The correct Answer is:
To find the original fundamental frequency \( f \) of the complete string given the fundamental frequencies \( f_1 \) and \( f_2 \) of the two segments, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the relationship between frequency and length**: The frequency of a vibrating string is inversely proportional to its length. This means that if a string has a longer length, it will have a lower frequency. \[ f \propto \frac{1}{L} \] 2. **Express frequencies in terms of lengths**: For the two segments of the string, we can express the frequencies \( f_1 \) and \( f_2 \) in terms of their respective lengths \( L_1 \) and \( L_2 \): \[ f_1 = \frac{k}{L_1} \quad \text{and} \quad f_2 = \frac{k}{L_2} \] Here, \( k \) is a constant. 3. **Express the total length**: The total length \( L \) of the string is the sum of the lengths of the two segments: \[ L = L_1 + L_2 \] 4. **Express the frequency of the complete string**: The frequency \( f \) of the complete string can be expressed as: \[ f = \frac{k}{L} \] 5. **Substitute lengths in terms of frequencies**: From the expressions for \( f_1 \) and \( f_2 \), we can express \( L_1 \) and \( L_2 \) in terms of \( f_1 \) and \( f_2 \): \[ L_1 = \frac{k}{f_1} \quad \text{and} \quad L_2 = \frac{k}{f_2} \] 6. **Substitute into the total length equation**: Substitute \( L_1 \) and \( L_2 \) into the equation for \( L \): \[ L = \frac{k}{f_1} + \frac{k}{f_2} \] 7. **Factor out \( k \)**: This gives us: \[ L = k \left( \frac{1}{f_1} + \frac{1}{f_2} \right) \] 8. **Substitute back into the frequency equation**: Now substitute this expression for \( L \) back into the equation for \( f \): \[ f = \frac{k}{L} = \frac{k}{k \left( \frac{1}{f_1} + \frac{1}{f_2} \right)} = \frac{1}{\left( \frac{1}{f_1} + \frac{1}{f_2} \right)} \] 9. **Simplify the expression**: This can be rewritten using the formula for the sum of fractions: \[ f = \frac{f_1 f_2}{f_1 + f_2} \] Thus, the original fundamental frequency \( f \) of the complete string is given by: \[ f = \frac{f_1 f_2}{f_1 + f_2} \]
Promotional Banner

Topper's Solved these Questions

  • WAVES

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT ( SECTION-C ( Previous year Questions ))|53 Videos
  • WAVES

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT ( SECTION-D ( Assertion - Reason Type Questions ))|12 Videos
  • WAVES

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT ( SECTION-A ( Objective type Questions ))|50 Videos
  • WAVE OPTICS

    AAKASH INSTITUTE ENGLISH|Exercise Assignment (Section-J (Aakash Challengers question))|1 Videos
  • WORK, ENERGY AND POWER

    AAKASH INSTITUTE ENGLISH|Exercise Assignment (SECTION - D)|13 Videos

Similar Questions

Explore conceptually related problems

If n_(1), n_(2 ) "and" n_(3) are the fundamental frequencies of three segments into which a string is divided, then the original fundamental frequency n of the string is given by

If v_(1) , v_(2) and v_(3) are the fundamental frequencies of three segments of stretched string , then the fundamental frequency of the overall string is

The fundamental frequency of a string is proportional to

When a string is divided into three segments of length l_1,l_2 and l_3 the fundamental frequencies of these three segments are f_1,f_2 and f_3 respectively. The original fundamental frequency f of the string is

If the speed of a transverse wave on a stretched string of length 1 m is 60 m s^-1 , what is the fundamental frequency of vibration ?

If the tension in a stretched string fixed at both ends is changed by 21% , the fundamental frequency is found to increase by 15 Hz , then the

For fundamental frequency f of a closed pipe, choose the correct options.

To decrease the fundamental frequency of a stretched string fixed at both ends one might

If the fundamental frequency of string is 220 cps , the frequency of fifth harmonic will be

If the length of a stretched string is shortened by 40 % and the tension is increased by 44 % , then the ratio of the final and initial fundamental frequencies is

AAKASH INSTITUTE ENGLISH-WAVES-ASSIGNMENT ( SECTION-B ( Objective type Questions ))
  1. Two sinusoidal waves are superposed. Their equations are y(1)=Asin(k...

    Text Solution

    |

  2. For an organ pipe, four of the six harmonics of frequency less than 10...

    Text Solution

    |

  3. A second harmonic has to be generated in a string of length L stretche...

    Text Solution

    |

  4. In a string wave , all particles of the medium cross the mean positio...

    Text Solution

    |

  5. Two waves represented by the following equations are travelling in the...

    Text Solution

    |

  6. In a closed end pipe of length 105 cm , standing waves are set up corr...

    Text Solution

    |

  7. A uniform string resonates with a tuning fork, at a maximum tension of...

    Text Solution

    |

  8. If in a stationary wave the amplitude corresponding to antinode is 4 c...

    Text Solution

    |

  9. If f(1) and f(2) be the fundamental frequencies of the two segments in...

    Text Solution

    |

  10. Two sound waves of intensity 2 W//m^(2) and 3W//m^(2) meet at a poin...

    Text Solution

    |

  11. The two waves of same frequency moving in the same direction give ris...

    Text Solution

    |

  12. The string of a violin emits a note of 205 Hz when its tension is corr...

    Text Solution

    |

  13. When two tuning forks (fork 1 and fork 2) are sounded simultaneously, ...

    Text Solution

    |

  14. A rocket is moving at a speed of 220 m s^(-1) towards a stationary tar...

    Text Solution

    |

  15. A source frequency f gives 5 beats when sounded with a frequency 200Hz...

    Text Solution

    |

  16. A vibrating tuning fork is moving slowly and uniformly ins a horizont...

    Text Solution

    |

  17. the frequency changes by 10 % as the source approaches a stationary ob...

    Text Solution

    |

  18. A train blowintg its whistle moves with constant - speed on a straigh...

    Text Solution

    |

  19. A man is standing on a railway platform listening to the whistle of an...

    Text Solution

    |

  20. A whistle 'S' of frequency v revolves in a circle of radius R at a con...

    Text Solution

    |