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The masses of the three wires of copper ...

The masses of the three wires of copper are in the ratio of `1:3:5` and their lengths are in the ratio of `5:3:1`. The ratio of their electrical resistance is

A

`125 : 15 : 1`

B

`1 : 15 : 125`

C

`5 : 3 : 1`

D

`1 : 3 : 5`

Text Solution

Verified by Experts

The correct Answer is:
A
`R = (rho L)/(A) therefore R prop (L^(2))/(m)`
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