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Two resistors of resistance R(1) and R(2...

Two resistors of resistance `R_(1)` and `R_(2)` having `R_(1) gt R_(2)` are connected in parallel. For equivalent resistance R, the correct statement is

A

`R gt r_(1) + r_(2)`

B

`R gt sqrt(r_(1) r_(2))`

C

`r_(1) lt R lt r_(2)`

D

`R lt r_(1)`

Text Solution

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The correct Answer is:
To solve the problem of finding the equivalent resistance \( R \) of two resistors \( R_1 \) and \( R_2 \) connected in parallel, we can follow these steps: ### Step 1: Understand the Parallel Connection In a parallel connection, the voltage across each resistor is the same, and the total current is the sum of the currents through each resistor. ### Step 2: Use the Formula for Equivalent Resistance The formula for the equivalent resistance \( R \) of two resistors \( R_1 \) and \( R_2 \) in parallel is given by: \[ \frac{1}{R} = \frac{1}{R_1} + \frac{1}{R_2} \] ### Step 3: Rearrange the Formula To find \( R \), we can rearrange the formula: \[ \frac{1}{R} = \frac{R_2 + R_1}{R_1 R_2} \] Thus, we can express \( R \) as: \[ R = \frac{R_1 R_2}{R_1 + R_2} \] ### Step 4: Analyze the Result Since \( R_1 > R_2 \), it follows that: - \( R_1 + R_2 > R_1 \) - \( R_1 + R_2 > R_2 \) This implies that: \[ R < R_1 \quad \text{and} \quad R < R_2 \] Therefore, the equivalent resistance \( R \) is less than either \( R_1 \) or \( R_2 \). ### Step 5: Conclusion The correct statement regarding the equivalent resistance \( R \) is that it is less than both \( R_1 \) and \( R_2 \).
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