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Coefficient of linear expnsion of mater...

Coefficient of linear expnsion of material of resistor is `alpha` . Its temperature coefficient of resistivity and resistance are `alpha_(p)` and `alpha_(R)` respectively , the correct relation is .

A

A. `alpha_(R) = alpha_(rho) - alpha`

B

B. `alpha_(R) = alpha_(rho) + alpha`

C

C. `alpha_(R) = alpha_(rho) + 3 alpha`

D

D. `alpha_(R) = alpha_(rho) - 3alpha`

Text Solution

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The correct Answer is:
To find the correct relation between the coefficient of linear expansion (α), the temperature coefficient of resistivity (α_p), and the temperature coefficient of resistance (α_R), we can follow these steps: ### Step 1: Understand the Definitions - **Coefficient of Linear Expansion (α)**: This defines how much a material expands per unit length for a unit increase in temperature. - **Temperature Coefficient of Resistivity (α_p)**: This defines how much the resistivity of a material changes with temperature. - **Temperature Coefficient of Resistance (α_R)**: This defines how much the resistance of a resistor changes with temperature. ### Step 2: Write the Resistance Formula The resistance \( R \) of a resistor can be expressed in terms of resistivity \( \rho \), length \( L \), and area \( A \): \[ R = \frac{\rho L}{A} \] ### Step 3: Express Changes in Length and Area When the temperature changes by \( \Delta T \): - The change in length \( L \) can be expressed as: \[ L = L_0 (1 + \alpha \Delta T) \] - The change in area \( A \) can be expressed as: \[ A = A_0 (1 + 2\alpha \Delta T) \] ### Step 4: Substitute Changes into the Resistance Formula Substituting the expressions for \( L \) and \( A \) into the resistance formula gives: \[ R = \frac{\rho (L_0 (1 + \alpha \Delta T))}{A_0 (1 + 2\alpha \Delta T)} \] ### Step 5: Express Changes in Resistivity The change in resistivity \( \rho \) can be expressed as: \[ \rho = \rho_0 (1 + \alpha_p \Delta T) \] ### Step 6: Substitute Resistivity into the Resistance Formula Substituting the expression for \( \rho \) into the resistance formula: \[ R = \frac{\rho_0 (1 + \alpha_p \Delta T) (L_0 (1 + \alpha \Delta T))}{A_0 (1 + 2\alpha \Delta T)} \] ### Step 7: Simplify the Expression For small changes in temperature, we can ignore higher-order terms: \[ R \approx R_0 (1 + \alpha_p \Delta T + \alpha \Delta T - 2\alpha \Delta T) \] This simplifies to: \[ R \approx R_0 (1 + (\alpha_p - \alpha) \Delta T) \] ### Step 8: Define the Temperature Coefficient of Resistance The temperature coefficient of resistance \( \alpha_R \) is defined as: \[ \alpha_R = \frac{1}{R_0} \frac{dR}{dT} \] From our expression, we can see that: \[ \alpha_R = \alpha_p - \alpha \] ### Conclusion Thus, the correct relation is: \[ \alpha_R = \alpha_p - \alpha \]
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