A flow of `10^(7)` electrons per second in a conducing wire constitutes a current of .

Options

A. `1.6 xx 10^(-12) A`
B. `1.6 xx 10^(26) A`
C. `1.6 xx 10^(- 26) A`
D. `1.6 xx 10^(12) A`

Answer

To find the current constituted by a flow of \(10^{7}\) electrons per second in a conducting wire, we can follow these steps:

### Step 1: Understand the relationship between current, charge, and time
The current \(I\) is defined as the rate of flow of charge. Mathematically, it is given by:
\[ I = \frac{dq}{dt} \]
where \(dq\) is the change in charge and \(dt\) is the change in time.

### Step 2: Determine the charge of one electron
The charge of a single electron is approximately:
\[ e = 1.6 \times 10^{-19} \text{ coulombs} \]

### Step 3: Calculate the total charge flowing per second
Given that \(10^{7}\) electrons flow per second, the total charge \(dq\) can be calculated as:
\[ dq = n \cdot e \]
where \(n\) is the number of electrons. Substituting the values:
\[ dq = 10^{7} \cdot (1.6 \times 10^{-19}) \text{ coulombs} \]

### Step 4: Perform the calculation
Now, we calculate \(dq\):
\[ dq = 10^{7} \cdot 1.6 \times 10^{-19} = 1.6 \times 10^{-12} \text{ coulombs} \]

### Step 5: Calculate the current
Since the flow is per second, we have \(dt = 1 \text{ second}\). Now we can find the current \(I\):
\[ I = \frac{dq}{dt} = \frac{1.6 \times 10^{-12}}{1} = 1.6 \times 10^{-12} \text{ amperes} \]

### Final Answer
Thus, the current constituted by a flow of \(10^{7}\) electrons per second is:
\[ I = 1.6 \times 10^{-12} \text{ A} \]

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